What are the solutions to the equation 4v^2-7v+1=0 ?

The solutions to the equation 4v^2-7v+1=0 are v=(7+sqrt(33))/8 ,v=(7-sqrt(33))/8

Find the zeros of 4v^2-7v+1=0

The zeros of 4v^2-7v+1=0 are v=(7+sqrt(33))/8 ,v=(7-sqrt(33))/8

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4 v^{2} - 7 v + 1 = 0

v = \frac{7 + 33}{8}, v = \frac{7 - 33}{8}

Decimal Notation

v = 1.59307 \dots, v = 0.15692 \dots

Solution steps

4 v^{2} - 7 v + 1 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 \cdot 1 = 33

v_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 4}, v_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 4}

v = \frac{- ( - 7 ) + 33}{2 \cdot 4} : \frac{7 + 33}{8}

v = \frac{- ( - 7 ) - 33}{2 \cdot 4} : \frac{7 - 33}{8}

The solutions to the quadratic equation are:

v = \frac{7 + 33}{8}, v = \frac{7 - 33}{8}

16 x^{2} - 4 x + \frac{1}{4} = 0

1 - 2 x > 0

\frac{( \frac{7}{25} )}{( - \frac{24}{25} )}

\frac{20 + 216}{2}

\frac{1}{3} x^{2} + \frac{1}{15} x - 1 = 0

What are the solutions to the equation 4v^2-7v+1=0 ?
The solutions to the equation 4v^2-7v+1=0 are v=(7+sqrt(33))/8 ,v=(7-sqrt(33))/8
Find the zeros of 4v^2-7v+1=0
The zeros of 4v^2-7v+1=0 are v=(7+sqrt(33))/8 ,v=(7-sqrt(33))/8