What are the solutions to the equation 1/3 x^2+1/15 x-1=0 ?

The solutions to the equation 1/3 x^2+1/15 x-1=0 are x=(-1+sqrt(301))/(10),x=(-1-sqrt(301))/(10)

Find the zeros of 1/3 x^2+1/15 x-1=0

The zeros of 1/3 x^2+1/15 x-1=0 are x=(-1+sqrt(301))/(10),x=(-1-sqrt(301))/(10)

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\frac{1}{3} x^{2} + \frac{1}{15} x - 1 = 0

x = \frac{- 1 + 301}{10}, x = \frac{- 1 - 301}{10}

Decimal Notation

x = 1.63493 \dots, x = - 1.83493 \dots

Solution steps

\frac{1}{3} x^{2} + \frac{1}{15} x - 1 = 0

Find Least Common Multiplier of

3, 15 : 15

Multiply by LCM=

15

\frac{1}{3} x^{2} \cdot 15 + \frac{1}{15} x \cdot 15 - 1 \cdot 15 = 0 \cdot 15

Simplify

5 x^{2} + x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 15 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 15) = 301

x_{1, 2} = \frac{- 1 \pm 301}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 301}{2 \cdot 5}, x_{2} = \frac{- 1 - 301}{2 \cdot 5}

x = \frac{- 1 + 301}{2 \cdot 5} : \frac{- 1 + 301}{10}

x = \frac{- 1 - 301}{2 \cdot 5} : \frac{- 1 - 301}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 301}{10}, x = \frac{- 1 - 301}{10}

\frac{2}{x + 1} \leq \frac{3}{x - 1}

x^{2} - 5 = 35

7 x (x - 1) = - 8 x^{2} + 4

lo g_{1} (1)

2 b^{2} + 10 b + 12

What are the solutions to the equation 1/3 x^2+1/15 x-1=0 ?
The solutions to the equation 1/3 x^2+1/15 x-1=0 are x=(-1+sqrt(301))/(10),x=(-1-sqrt(301))/(10)
Find the zeros of 1/3 x^2+1/15 x-1=0
The zeros of 1/3 x^2+1/15 x-1=0 are x=(-1+sqrt(301))/(10),x=(-1-sqrt(301))/(10)