What are the solutions to the equation 7x(x-1)=-8x^2+4 ?

The solutions to the equation 7x(x-1)=-8x^2+4 are x= 4/5 ,x=-1/3

Find the zeros of 7x(x-1)=-8x^2+4

The zeros of 7x(x-1)=-8x^2+4 are x= 4/5 ,x=-1/3

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7 x (x - 1) = - 8 x^{2} + 4

x = \frac{4}{5}, x = - \frac{1}{3}

Decimal Notation

x = 0.8, x = - 0.33333 \dots

Solution steps

7 x (x - 1) = - 8 x^{2} + 4

Expand

7 x (x - 1) : 7 x^{2} - 7 x

7 x^{2} - 7 x = - 8 x^{2} + 4

Move

4

to the left side

7 x^{2} - 7 x - 4 = - 8 x^{2}

Move

8 x^{2}

to the left side

15 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 15 ( - 4 )}{2 \cdot 15}

(- 7)^{2} - 4 \cdot 15 (- 4) = 17

x_{1, 2} = \frac{- ( - 7 ) \pm 17}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 17}{2 \cdot 15}, x_{2} = \frac{- ( - 7 ) - 17}{2 \cdot 15}

x = \frac{- ( - 7 ) + 17}{2 \cdot 15} : \frac{4}{5}

x = \frac{- ( - 7 ) - 17}{2 \cdot 15} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - \frac{1}{3}

lo g_{1} (1)

2 b^{2} + 10 b + 12

- 5 + 21 x - 4 x^{2} = 0

x^{2} - 3 x - 10 > 0

\frac{4 x + 4}{5} = - 12

What are the solutions to the equation 7x(x-1)=-8x^2+4 ?
The solutions to the equation 7x(x-1)=-8x^2+4 are x= 4/5 ,x=-1/3
Find the zeros of 7x(x-1)=-8x^2+4
The zeros of 7x(x-1)=-8x^2+4 are x= 4/5 ,x=-1/3