What are the solutions to the equation -5+21x-4x^2=0 ?

The solutions to the equation -5+21x-4x^2=0 are x= 1/4 ,x=5

Find the zeros of -5+21x-4x^2=0

The zeros of -5+21x-4x^2=0 are x= 1/4 ,x=5

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- 5 + 21 x - 4 x^{2} = 0

x = \frac{1}{4}, x = 5

Decimal Notation

x = 0.25, x = 5

Solution steps

- 5 + 21 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 21 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 ( - 4 ) ( - 5 )}{2 ( - 4 )}

2 1^{2} - 4 (- 4) (- 5) = 19

x_{1, 2} = \frac{- 21 \pm 19}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 21 + 19}{2 ( - 4 )}, x_{2} = \frac{- 21 - 19}{2 ( - 4 )}

x = \frac{- 21 + 19}{2 ( - 4 )} : \frac{1}{4}

x = \frac{- 21 - 19}{2 ( - 4 )} : 5

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 5

x^{2} - 3 x - 10 > 0

\frac{4 x + 4}{5} = - 12

2 (- 11 y + 4)^{2} - 5 y - 9 = 0

1 - x - 2 x^{2} \geq 0

- 43 z \geq 3

What are the solutions to the equation -5+21x-4x^2=0 ?
The solutions to the equation -5+21x-4x^2=0 are x= 1/4 ,x=5
Find the zeros of -5+21x-4x^2=0
The zeros of -5+21x-4x^2=0 are x= 1/4 ,x=5