What are the solutions to the equation 33-33x=(6x+3)(x-1) ?

The solutions to the equation 33-33x=(6x+3)(x-1) are x=1,x=-6

Find the zeros of 33-33x=(6x+3)(x-1)

The zeros of 33-33x=(6x+3)(x-1) are x=1,x=-6

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33 - 33 x = (6 x + 3) (x - 1)

x = 1, x = - 6

Solution steps

33 - 33 x = (6 x + 3) (x - 1)

Expand

(6 x + 3) (x - 1) : 6 x^{2} - 3 x - 3

33 - 33 x = 6 x^{2} - 3 x - 3

Switch sides

6 x^{2} - 3 x - 3 = 33 - 33 x

Move

33 x

to the left side

6 x^{2} + 30 x - 3 = 33

Move

33

to the left side

6 x^{2} + 30 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 6 ( - 36 )}{2 \cdot 6}

3 0^{2} - 4 \cdot 6 (- 36) = 42

x_{1, 2} = \frac{- 30 \pm 42}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 30 + 42}{2 \cdot 6}, x_{2} = \frac{- 30 - 42}{2 \cdot 6}

x = \frac{- 30 + 42}{2 \cdot 6} : 1

x = \frac{- 30 - 42}{2 \cdot 6} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

6 x^{2} + 13 x + 2

\frac{3}{4} + \frac{1}{2} - \frac{3}{8}

- 12 = 9 - 3 w

4 = (x + 5)^{2}

What are the solutions to the equation 33-33x=(6x+3)(x-1) ?
The solutions to the equation 33-33x=(6x+3)(x-1) are x=1,x=-6
Find the zeros of 33-33x=(6x+3)(x-1)
The zeros of 33-33x=(6x+3)(x-1) are x=1,x=-6