What are the solutions to the equation r^2+4=0 ?

The solutions to the equation r^2+4=0 are r=2i,r=-2i

Find the zeros of r^2+4=0

The zeros of r^2+4=0 are r=2i,r=-2i

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r^{2} + 4 = 0

r = 2 i, r = - 2 i

Solution steps

r^{2} + 4 = 0

Move

4

to the right side

r^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 4, r = - - 4

- 4 = 2 i

- - 4 = - 2 i

r = 2 i, r = - 2 i

(2 x + 9)^{2} - 72 = 0

\frac{7}{6} - \frac{9}{2} + \frac{11}{3} - \frac{5}{12}

5 x - 15 = 2 x + 21

x^{3} - 7 x^{2} + 11 x + 3

- \frac{5 π}{4} - 2 π

What are the solutions to the equation r^2+4=0 ?
The solutions to the equation r^2+4=0 are r=2i,r=-2i
Find the zeros of r^2+4=0
The zeros of r^2+4=0 are r=2i,r=-2i