What are the solutions to the equation x^2-18x+85=0 ?

The solutions to the equation x^2-18x+85=0 are x=9+2i,x=9-2i

Find the zeros of x^2-18x+85=0

The zeros of x^2-18x+85=0 are x=9+2i,x=9-2i

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x^{2} - 18 x + 85 = 0

x = 9 + 2 i, x = 9 - 2 i

Solution steps

x^{2} - 18 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 85 : 4 i

x_{1, 2} = \frac{- ( - 18 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 18 ) + 4 i}{2 \cdot 1} : 9 + 2 i

x = \frac{- ( - 18 ) - 4 i}{2 \cdot 1} : 9 - 2 i

The solutions to the quadratic equation are:

x = 9 + 2 i, x = 9 - 2 i

\frac{3}{4} \cdot 4 - 1

2 x^{2} - 9 x - 8 = 0

- 2 k > 18

(x - 3)^{2} = 81

- 243

What are the solutions to the equation x^2-18x+85=0 ?
The solutions to the equation x^2-18x+85=0 are x=9+2i,x=9-2i
Find the zeros of x^2-18x+85=0
The zeros of x^2-18x+85=0 are x=9+2i,x=9-2i