What is sqrt((5x+1)/(1+4x))>= 0 ?

The solution to sqrt((5x+1)/(1+4x))>= 0 is x =-1/5

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sqrt((5x+1)/(1+4x))>= 0

\frac{5 x + 1}{1 + 4 x} \geq 0

x < - \frac{1}{4} or x \geq - \frac{1}{5}

Interval Notation

(- \infty, - \frac{1}{4}) \cup [- \frac{1}{5}, \infty)

Decimal Notation

x < - 0.25 or x \geq - 0.2

Solution steps

\frac{5 x + 1}{1 + 4 x} \geq 0

If n is even,

for all

u

True for all x

Find singularity points

Find non-negative values for radicals:

x < - \frac{1}{4} or x \geq - \frac{1}{5}

Combine the intervals

True for all x and (x < - \frac{1}{4} or x \geq - \frac{1}{5})

Merge Overlapping Intervals

x < - \frac{1}{4} or x \geq - \frac{1}{5}

(a b^{- 3})^{- 1}

- 4 x^{2} - 15 x + 4 = 0

\frac{x}{4} + 1 = 2

\frac{k}{2 k + 1} + \frac{1}{( 2 k + 1 ) ( 2 k + 3 )}

3 x^{2} - 2 x (x - 4) = x - 12

What is sqrt((5x+1)/(1+4x))>= 0 ?
The solution to sqrt((5x+1)/(1+4x))>= 0 is x<-1/4 \lor x>=-1/5