What is |h-0.018|<= 0.001 ?

The solution to |h-0.018|<= 0.001 is 0.017<= h<= 0.019

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|h-0.018|<= 0.001

∣ h - 0.018 ∣ \leq 0.001

0.017 \leq h \leq 0.019

Interval Notation

[0.017, 0.019]

Solution steps

∣ h - 0.018 ∣ \leq 0.001

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 0.001 \leq h - 0.018 \leq 0.001

h - 0.018 \geq - 0.001 and h - 0.018 \leq 0.001

h \geq 0.017 and h \leq 0.019

Merge Overlapping Intervals

0.017 \leq h \leq 0.019

\frac{3}{5} + \frac{7}{15}

\frac{3 - 2 x}{5} < 4 \leq \frac{1 - x}{2}

\frac{0.5 ( 9.1 - 7.3 ) ^{2}}{5.8 + 8.6 - 5.4}

5 - b = 1

5^{n} - 5^{n - 3}

What is |h-0.018|<= 0.001 ?
The solution to |h-0.018|<= 0.001 is 0.017<= h<= 0.019