What is log_{4}(2x^2+3x+1)>= log_{2}(2x+2) ?

The solution to log_{4}(2x^2+3x+1)>= log_{2}(2x+2) is No Solution

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log_{4}(2x^2+3x+1)>= log_{2}(2x+2)

lo g_{4} (2 x^{2} + 3 x + 1) \geq lo g_{2} (2 x + 2)

No Solution

Solution steps

lo g_{4} (2 x^{2} + 3 x + 1) \geq lo g_{2} (2 x + 2)

Apply log rules

2 x^{2} + 3 x + 1 \geq 2 x + 2 and 2 x + 2 > 0

2 x^{2} + 3 x + 1 \geq 2 x + 2 and 2 x + 2 > 0 :

No Solution

No Solution for x \in R

x^{3} - 3 x^{2} - 13 x + 15

x^{2} + (x + 4)^{2} = 2 0^{2}

5 (x - 6) + 3 = 18 - (3 + 2 x)

3 + 4 c = 15

\frac{8 x ^{2} y ^{2} - 10 x y ^{3} - 5 y}{2 y ^{2}}

What is log_{4}(2x^2+3x+1)>= log_{2}(2x+2) ?
The solution to log_{4}(2x^2+3x+1)>= log_{2}(2x+2) is No Solution