What is (8x^2y^2-10xy^3-5y)/(2y^2) ?

The solution to (8x^2y^2-10xy^3-5y)/(2y^2) is (8x^2y-10xy^2-5)/(2y)

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simplify (8x^2y^2-10xy^3-5y)/(2y^2)

simplify

\frac{8 x ^{2} y ^{2} - 10 x y ^{3} - 5 y}{2 y ^{2}}

\frac{8 x ^{2} y - 10 x y ^{2} - 5}{2 y}

Solution steps

\frac{8 x ^{2} y ^{2} - 10 x y ^{3} - 5 y}{2 y ^{2}}

Factor

8 x^{2} y^{2} - 10 x y^{3} - 5 y : y (8 x^{2} y - 10 x y^{2} - 5)

= \frac{y ( 8 x ^{2} y - 10 x y ^{2} - 5 )}{2 y ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

y^{2} = yy

= \frac{y ( 8 x ^{2} y - 10 x y ^{2} - 5 )}{2 yy}

Cancel the common factor:

y

= \frac{8 x ^{2} y - 10 x y ^{2} - 5}{2 y}

- 2 x - 4 = - 16

3^{2} + 2^{3}

\frac{( 2 + 1 )}{2} \geq 3

x (2 x - 5) = 12

x^{\frac{7}{2}} - x^{\frac{3}{2}}

What is (8x^2y^2-10xy^3-5y)/(2y^2) ?
The solution to (8x^2y^2-10xy^3-5y)/(2y^2) is (8x^2y-10xy^2-5)/(2y)