What are the solutions to the equation r^2-6r+25=0 ?

The solutions to the equation r^2-6r+25=0 are r=3+4i,r=3-4i

Find the zeros of r^2-6r+25=0

The zeros of r^2-6r+25=0 are r=3+4i,r=3-4i

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r^{2} - 6 r + 25 = 0

r = 3 + 4 i, r = 3 - 4 i

Solution steps

r^{2} - 6 r + 25 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 25 : 8 i

r_{1, 2} = \frac{- ( - 6 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 8 i}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 8 i}{2 \cdot 1}

r = \frac{- ( - 6 ) + 8 i}{2 \cdot 1} : 3 + 4 i

r = \frac{- ( - 6 ) - 8 i}{2 \cdot 1} : 3 - 4 i

The solutions to the quadratic equation are:

r = 3 + 4 i, r = 3 - 4 i

3^{\frac{1}{3}} \cdot 9^{\frac{1}{3}}

4 x^{2} - 9 x + 17 = - 4 x + 8

4 y^{2} - 8 y - 5

(x - 4) = 6

2 x^{2} - \frac{11}{2} x - \frac{3}{2} = 0

What are the solutions to the equation r^2-6r+25=0 ?
The solutions to the equation r^2-6r+25=0 are r=3+4i,r=3-4i
Find the zeros of r^2-6r+25=0
The zeros of r^2-6r+25=0 are r=3+4i,r=3-4i