What is factor 4x^2-20xy+25y^2 ?

The solution to factor 4x^2-20xy+25y^2 is (2x-5y)^2

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factor 4x^2-20xy+25y^2

factor

4 x^{2} - 20 x y + 25 y^{2}

(2 x - 5 y)^{2}

Solution steps

4 x^{2} - 20 x y + 25 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 x^{2} = (2 x)^{2}

25 y^{2} = (5 y)^{2}

- 20 x y = - 2 \cdot 2 x \cdot 5 y

= (2 x)^{2} - 2 \cdot 2 x \cdot 5 y + (5 y)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 x)^{2} - 2 \cdot 2 x \cdot 5 y + (5 y)^{2} = (2 x - 5 y)^{2}

= (2 x - 5 y)^{2}

- 2 x^{2} + 17 = 8 x - 1

x^{3} \cdot x^{5}

\frac{0.022 ( 0.0016 ) ^{2}}{2}

12 m^{2} n + 24 m^{3} n^{2} - 36 m^{4} n + 48 m^{5} n^{4}

x^{2} = 8 x - 9

What is factor 4x^2-20xy+25y^2 ?
The solution to factor 4x^2-20xy+25y^2 is (2x-5y)^2