What is -3x^4<3\land 4x+6<-3 ?

The solution to -3x^4<3\land 4x+6<-3 is x<-9/4

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-3x^4<3\land 4x+6<-3

- 3 x^{4} < 3 and 4 x + 6 < - 3

x < - \frac{9}{4}

Interval Notation

(- \infty, - \frac{9}{4})

Decimal Notation

x < - 2.25

Solution steps

- 3 x^{4} < 3 and 4 x + 6 < - 3

- 3 x^{4} < 3 :

True for all

x

4 x + 6 < - 3 : x < - \frac{9}{4}

Combine the intervals

True for all x and x < - \frac{9}{4}

Merge Overlapping Intervals

x < - \frac{9}{4}

∣ 12 - 4 x ∣ \geq 0

(x - 8)^{2} = 64

15 (x - 1) = - 5 (3 - x) + 10 x

x^{2} + 3 x = 18

4 y^{2} + 16 y + 15