What is 4x(x-1)*(x+1)>= 0 ?

The solution to 4x(x-1)*(x+1)>= 0 is -1 = 1

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4x(x-1)*(x+1)>= 0

4 x (x - 1) \cdot (x + 1) \geq 0

- 1 \leq x \leq 0 or x \geq 1

Interval Notation

[- 1, 0] \cup [1, \infty)

Solution steps

4 x (x - 1) (x + 1) \geq 0

Rewrite in standard form

x^{3} - x \geq 0

Factor

x^{3} - x : x (x + 1) (x - 1)

x (x + 1) (x - 1) \geq 0

Identify the intervals

- 1 \leq x \leq 0 or x \geq 1

(- 4)^{3}

x^{2} - 5 x y + 6 y^{2}

\frac{x + 16}{x - 5} \geq 0

x^{4} - y^{4}

2 n^{2} - 3 n - 9

What is 4x(x-1)*(x+1)>= 0 ?
The solution to 4x(x-1)*(x+1)>= 0 is -1<= x<= 0\lor x>= 1