What is (4a)^{-3}*a^{-4} ?

The solution to (4a)^{-3}*a^{-4} is 1/(64a^7)

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simplify (4a)^{-3}*a^{-4}

simplify

(4 a)^{- 3} \cdot a^{- 4}

\frac{1}{64 a ^{7}}

Solution steps

(4 a)^{- 3} a^{- 4}

Simplify

(4 a)^{- 3} : \frac{1}{64 a ^{3}}

= \frac{1}{64 a ^{3}} a^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

a^{- 4} = \frac{1}{a ^{4}}

= \frac{1}{64 a ^{3}} \cdot \frac{1}{a ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{64 a ^{3} a ^{4}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{64 a ^{3} a ^{4}}

Simplify

a^{3} a^{4} : a^{7}

= \frac{1}{64 a ^{7}}

x^{2} + 7 x = - 12

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2

(3 x - 5)^{2} + 7 (3 x - 5) + 12 = 0

∣ 8 - 4 x ∣ \leq 3

\frac{- n ^{2} + 16 n - 63}{n ^{2} - 2 n - 35}