What are the solutions to the equation 6(x-2)^2+24(x-2)-1=0 ?

The solutions to the equation 6(x-2)^2+24(x-2)-1=0 are x= 5/(sqrt(6)),x=-5/(sqrt(6))

Find the zeros of 6(x-2)^2+24(x-2)-1=0

The zeros of 6(x-2)^2+24(x-2)-1=0 are x= 5/(sqrt(6)),x=-5/(sqrt(6))

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6 (x - 2)^{2} + 24 (x - 2) - 1 = 0

x = \frac{5}{6}, x = - \frac{5}{6}

Decimal Notation

x = 2.04124 \dots, x = - 2.04124 \dots

Solution steps

6 (x - 2)^{2} + 24 (x - 2) - 1 = 0

Expand

6 (x - 2)^{2} + 24 (x - 2) - 1 : 6 x^{2} - 25

6 x^{2} - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 6 ( - 25 )}{2 \cdot 6}

0^{2} - 4 \cdot 6 (- 25) = 106

x_{1, 2} = \frac{- 0 \pm 10 6}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 0 + 10 6}{2 \cdot 6}, x_{2} = \frac{- 0 - 10 6}{2 \cdot 6}

x = \frac{- 0 + 10 6}{2 \cdot 6} : \frac{5}{6}

x = \frac{- 0 - 10 6}{2 \cdot 6} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - \frac{5}{6}

x^{2} - 6 x + 6 = 0

8 x - 21 = 2 x - 9

x - 9 = 12

10 ∣ - 2 n + 4 ∣ - 5 < 15

What are the solutions to the equation 6(x-2)^2+24(x-2)-1=0 ?
The solutions to the equation 6(x-2)^2+24(x-2)-1=0 are x= 5/(sqrt(6)),x=-5/(sqrt(6))
Find the zeros of 6(x-2)^2+24(x-2)-1=0
The zeros of 6(x-2)^2+24(x-2)-1=0 are x= 5/(sqrt(6)),x=-5/(sqrt(6))