What are the solutions to the equation x^2+20=4 ?

The solutions to the equation x^2+20=4 are x=4i,x=-4i

Find the zeros of x^2+20=4

The zeros of x^2+20=4 are x=4i,x=-4i

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x^{2} + 20 = 4

x = 4 i, x = - 4 i

Solution steps

x^{2} + 20 = 4

Move

20

to the right side

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

3 x^{2} - 16 x + 15 = 3

\frac{6}{3 !}

2 \cdot \frac{\frac{1}{2}}{5} = \frac{p}{4}

x^{2} + 4 x - 12 \geq 0

6 x + 8 y

What are the solutions to the equation x^2+20=4 ?
The solutions to the equation x^2+20=4 are x=4i,x=-4i
Find the zeros of x^2+20=4
The zeros of x^2+20=4 are x=4i,x=-4i