What are the solutions to the equation x^2+18x-19=0 ?

The solutions to the equation x^2+18x-19=0 are x=1,x=-19

Find the zeros of x^2+18x-19=0

The zeros of x^2+18x-19=0 are x=1,x=-19

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x^{2} + 18 x - 19 = 0

x = 1, x = - 19

Solution steps

x^{2} + 18 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 19) = 20

x_{1, 2} = \frac{- 18 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 20}{2 \cdot 1}, x_{2} = \frac{- 18 - 20}{2 \cdot 1}

x = \frac{- 18 + 20}{2 \cdot 1} : 1

x = \frac{- 18 - 20}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

x = 1, x = - 19

40 = \frac{8}{5} u

- 7 (2.45 + v) = 12.2

3 x^{2} + 2 x - 2 = 0

5 k^{2} + 30 + 25 k

What are the solutions to the equation x^2+18x-19=0 ?
The solutions to the equation x^2+18x-19=0 are x=1,x=-19
Find the zeros of x^2+18x-19=0
The zeros of x^2+18x-19=0 are x=1,x=-19