What are the solutions to the equation 3x^2+2x-2=0 ?

The solutions to the equation 3x^2+2x-2=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3

Find the zeros of 3x^2+2x-2=0

The zeros of 3x^2+2x-2=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3

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3 x^{2} + 2 x - 2 = 0

x = \frac{- 1 + 7}{3}, x = - \frac{1 + 7}{3}

Decimal Notation

x = 0.54858 \dots, x = - 1.21525 \dots

Solution steps

3 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 2) = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 7}{2 \cdot 3}

x = \frac{- 2 + 2 7}{2 \cdot 3} : \frac{- 1 + 7}{3}

x = \frac{- 2 - 2 7}{2 \cdot 3} : - \frac{1 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{3}, x = - \frac{1 + 7}{3}

5 k^{2} + 30 + 25 k

2 k^{2} = 9 + 3 k

\frac{1}{3} \cdot \frac{1}{7}

5 t^{2} - 20 + 3 t^{3} - 12 t

What are the solutions to the equation 3x^2+2x-2=0 ?
The solutions to the equation 3x^2+2x-2=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3
Find the zeros of 3x^2+2x-2=0
The zeros of 3x^2+2x-2=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3