What are the solutions to the equation 10t^2-29t=-10 ?

The solutions to the equation 10t^2-29t=-10 are t= 5/2 ,t= 2/5

Find the zeros of 10t^2-29t=-10

The zeros of 10t^2-29t=-10 are t= 5/2 ,t= 2/5

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10 t^{2} - 29 t = - 10

t = \frac{5}{2}, t = \frac{2}{5}

Decimal Notation

t = 2.5, t = 0.4

Solution steps

10 t^{2} - 29 t = - 10

Move

10

to the left side

10 t^{2} - 29 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 29)^{2} - 4 \cdot 10 \cdot 10 = 21

t_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 10}

Separate the solutions

t_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 10}, t_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 10}

t = \frac{- ( - 29 ) + 21}{2 \cdot 10} : \frac{5}{2}

t = \frac{- ( - 29 ) - 21}{2 \cdot 10} : \frac{2}{5}

The solutions to the quadratic equation are:

t = \frac{5}{2}, t = \frac{2}{5}

2 x^{2} + 3 x = - 10

8 - 7 x > - 5

x^{3} \cdot x^{6}

x - 7 > - 13

What are the solutions to the equation 10t^2-29t=-10 ?
The solutions to the equation 10t^2-29t=-10 are t= 5/2 ,t= 2/5
Find the zeros of 10t^2-29t=-10
The zeros of 10t^2-29t=-10 are t= 5/2 ,t= 2/5