What is factor 4y^2+8y-5 ?

The solution to factor 4y^2+8y-5 is (2y-1)(2y+5)

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factor 4y^2+8y-5

factor

4 y^{2} + 8 y - 5

(2 y - 1) (2 y + 5)

Solution steps

4 y^{2} + 8 y - 5

Break the expression into groups

= (4 y^{2} - 2 y) + (10 y - 5)

Factor out

2 y

from

4 y^{2} - 2 y : 2 y (2 y - 1)

Factor out

5

from

10 y - 5 : 5 (2 y - 1)

= 2 y (2 y - 1) + 5 (2 y - 1)

Factor out common term

2 y - 1

= (2 y - 1) (2 y + 5)

\frac{r ^{7} n ^{7} t ^{2}}{n ^{3} r ^{3} t ^{2}}

3 x^{3} - 2 x^{2} - 9 x + 6

45 \cdot 5

2 x^{2} + 12 x = - 18

4 - 8 i