What are the solutions to the equation 2t^2-5t=3 ?

The solutions to the equation 2t^2-5t=3 are t=3,t=-1/2

Find the zeros of 2t^2-5t=3

The zeros of 2t^2-5t=3 are t=3,t=-1/2

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2 t^{2} - 5 t = 3

t = 3, t = - \frac{1}{2}

Decimal Notation

t = 3, t = - 0.5

Solution steps

2 t^{2} - 5 t = 3

Move

3

to the left side

2 t^{2} - 5 t - 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

t_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, t_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

t = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

t = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

t = 3, t = - \frac{1}{2}

- [- 2 y + 6 (2 y - 7)] = 10 (1 - y) - 16 (4 y + 6)

6 x^{2} + 7 x - 2 = 0

3 b^{4} - 6 b^{2} + 27 b

\frac{2 n !}{2 ^{n} n !}

3 x^{2} - 4 x - 8 = 0

What are the solutions to the equation 2t^2-5t=3 ?
The solutions to the equation 2t^2-5t=3 are t=3,t=-1/2
Find the zeros of 2t^2-5t=3
The zeros of 2t^2-5t=3 are t=3,t=-1/2