What are the solutions to the equation -x^2+7x+5=0 ?

The solutions to the equation -x^2+7x+5=0 are x=-(-7+sqrt(69))/2 ,x=(7+sqrt(69))/2

Find the zeros of -x^2+7x+5=0

The zeros of -x^2+7x+5=0 are x=-(-7+sqrt(69))/2 ,x=(7+sqrt(69))/2

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- x^{2} + 7 x + 5 = 0

x = - \frac{- 7 + 69}{2}, x = \frac{7 + 69}{2}

Decimal Notation

x = - 0.65331 \dots, x = 7.65331 \dots

Solution steps

- x^{2} + 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

7^{2} - 4 (- 1) \cdot 5 = 69

x_{1, 2} = \frac{- 7 \pm 69}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 69}{2 ( - 1 )}, x_{2} = \frac{- 7 - 69}{2 ( - 1 )}

x = \frac{- 7 + 69}{2 ( - 1 )} : - \frac{- 7 + 69}{2}

x = \frac{- 7 - 69}{2 ( - 1 )} : \frac{7 + 69}{2}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 69}{2}, x = \frac{7 + 69}{2}

147 m^{3} n^{3}

2 (\frac{1}{2})^{- 1}

- 7 d + 8 > 29

6 x^{2} - 19 x y + 15 y^{2}

3 x^{2} - 7 x^{2} + 2 \geq 0

What are the solutions to the equation -x^2+7x+5=0 ?
The solutions to the equation -x^2+7x+5=0 are x=-(-7+sqrt(69))/2 ,x=(7+sqrt(69))/2
Find the zeros of -x^2+7x+5=0
The zeros of -x^2+7x+5=0 are x=-(-7+sqrt(69))/2 ,x=(7+sqrt(69))/2