What are the solutions to the equation -2t^2-42=48 ?

The solutions to the equation -2t^2-42=48 are t=3sqrt(5)i,t=-3sqrt(5)i

Find the zeros of -2t^2-42=48

The zeros of -2t^2-42=48 are t=3sqrt(5)i,t=-3sqrt(5)i

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- 2 t^{2} - 42 = 48

t = 35 i, t = - 35 i

Solution steps

- 2 t^{2} - 42 = 48

Move

42

to the right side

- 2 t^{2} = 90

Divide both sides by

- 2

t^{2} = - 45

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - 45, t = - - 45

- 45 = 35 i

- - 45 = - 35 i

t = 35 i, t = - 35 i

4 (w + 1) - 7 = 3 (w - 1) + w

3 x^{2} - 2 x - 4 = 0

\frac{2}{3} + 5

8 x^{\frac{7}{3}} + 24 x^{\frac{4}{3}} + 18 x^{\frac{1}{3}}

- 0.1 x^{2} + 90 x = 20250

What are the solutions to the equation -2t^2-42=48 ?
The solutions to the equation -2t^2-42=48 are t=3sqrt(5)i,t=-3sqrt(5)i
Find the zeros of -2t^2-42=48
The zeros of -2t^2-42=48 are t=3sqrt(5)i,t=-3sqrt(5)i