What are the solutions to the equation x^2=4x-11 ?

The solutions to the equation x^2=4x-11 are x=2+sqrt(7)i,x=2-sqrt(7)i

Find the zeros of x^2=4x-11

The zeros of x^2=4x-11 are x=2+sqrt(7)i,x=2-sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = 4 x - 11

x = 2 + 7 i, x = 2 - 7 i

Solution steps

x^{2} = 4 x - 11

Move

11

to the left side

x^{2} + 11 = 4 x

Move

4 x

to the left side

x^{2} + 11 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 11 : 27 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 7 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 7 i}{2 \cdot 1} : 2 + 7 i

x = \frac{- ( - 4 ) - 2 7 i}{2 \cdot 1} : 2 - 7 i

The solutions to the quadratic equation are:

x = 2 + 7 i, x = 2 - 7 i

4 x^{2} + 8 x = - 4

\frac{x ^{- 4} y ^{- 5} y ^{2}}{x}

(- 2)^{- 2}

\frac{7 - x}{x - 5} \geq - 3

- 2.4 (2) + 9.6

What are the solutions to the equation x^2=4x-11 ?
The solutions to the equation x^2=4x-11 are x=2+sqrt(7)i,x=2-sqrt(7)i
Find the zeros of x^2=4x-11
The zeros of x^2=4x-11 are x=2+sqrt(7)i,x=2-sqrt(7)i