What are the solutions to the equation x^2+10x+25=7 ?

The solutions to the equation x^2+10x+25=7 are x=-5+sqrt(7),x=-5-sqrt(7)

Find the zeros of x^2+10x+25=7

The zeros of x^2+10x+25=7 are x=-5+sqrt(7),x=-5-sqrt(7)

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x^{2} + 10 x + 25 = 7

x = - 5 + 7, x = - 5 - 7

Solution steps

x^{2} + 10 x + 25 = 7

Move

7

to the left side

x^{2} + 10 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 18 = 27

x_{1, 2} = \frac{- 10 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 7}{2 \cdot 1}

x = \frac{- 10 + 2 7}{2 \cdot 1} : - 5 + 7

x = \frac{- 10 - 2 7}{2 \cdot 1} : - 5 - 7

The solutions to the quadratic equation are:

x = - 5 + 7, x = - 5 - 7

6 4^{\frac{2}{3}} 6 4^{\frac{2}{3}}

n^{2} - n - 20

14 x^{2} - 28 = 0

- 5 m^{2} - 15 m + 50

8 k^{2} - 18

What are the solutions to the equation x^2+10x+25=7 ?
The solutions to the equation x^2+10x+25=7 are x=-5+sqrt(7),x=-5-sqrt(7)
Find the zeros of x^2+10x+25=7
The zeros of x^2+10x+25=7 are x=-5+sqrt(7),x=-5-sqrt(7)