What is ((x^{-7}y^6)/(x^{-4)y^4})^2 ?

The solution to ((x^{-7}y^6)/(x^{-4)y^4})^2 is (y^4)/(x^6)

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simplify ((x^{-7}y^6)/(x^{-4)y^4})^2

simplify

(\frac{x ^{- 7} y ^{6}}{x ^{- 4} y ^{4}})^{2}

\frac{y ^{4}}{x ^{6}}

Solution steps

(\frac{x ^{- 7} y ^{6}}{x ^{- 4} y ^{4}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{- 7} y ^{6} ) ^{2}}{( x ^{- 4} y ^{4} ) ^{2}}

Simplify

(x^{- 7} y^{6})^{2} : \frac{y ^{12}}{x ^{14}}

= \frac{\frac{y ^{12}}{x ^{14}}}{( x ^{- 4} y ^{4} ) ^{2}}

Simplify

(x^{- 4} y^{4})^{2} : \frac{y ^{8}}{x ^{8}}

= \frac{\frac{y ^{12}}{x ^{14}}}{\frac{y ^{8}}{x ^{8}}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{y ^{12} x ^{8}}{x ^{14} y ^{8}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{y ^{12}}{y ^{8}} = y^{12 - 8}

= \frac{x ^{8} y ^{12 - 8}}{x ^{14}}

Subtract the numbers:

12 - 8 = 4

= \frac{x ^{8} y ^{4}}{x ^{14}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{8}}{x ^{14}} = \frac{1}{x ^{14 - 8}}

= \frac{y ^{4}}{x ^{14 - 8}}

Subtract the numbers:

14 - 8 = 6

= \frac{y ^{4}}{x ^{6}}

5 x^{2} - 13 x = 0

2 (x - 2 (3 - x)) < 5 + 2 x

\frac{36}{100}

27 x^{4} - 147

10 x^{2} - 19 x - 15 = 0

What is ((x^{-7}y^6)/(x^{-4)y^4})^2 ?
The solution to ((x^{-7}y^6)/(x^{-4)y^4})^2 is (y^4)/(x^6)