What is (-(3x^4)/(2y^5))^{-3} ?

The solution to (-(3x^4)/(2y^5))^{-3} is -(8y^{15})/(27x^{12)}

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simplify (-(3x^4)/(2y^5))^{-3}

simplify

(- \frac{3 x ^{4}}{2 y ^{5}})^{- 3}

- \frac{8 y ^{15}}{27 x ^{12}}

Solution steps

(- \frac{3 x ^{4}}{2 y ^{5}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(- \frac{3 x ^{4}}{2 y ^{5}})^{- 3} = \frac{1}{( - \frac{3 x ^{4}}{2 y ^{5}} ) ^{3}}

= \frac{1}{( - \frac{3 x ^{4}}{2 y ^{5}} ) ^{3}}

Simplify

(- \frac{3 x ^{4}}{2 y ^{5}})^{3} : - \frac{27 x ^{12}}{8 y ^{15}}

= \frac{1}{- \frac{27 x ^{12}}{8 y ^{15}}}

Simplify

\frac{1}{- \frac{27 x ^{12}}{8 y ^{15}}} : - \frac{8 y ^{15}}{27 x ^{12}}

= - \frac{8 y ^{15}}{27 x ^{12}}

\frac{( 1 + i ) ^{17}}{( 1 - i ) ^{16}}

\frac{2}{9} \cdot \frac{1}{8}

3 (x + 3)^{2} = 27

\frac{2 t x}{t ^{2} - x ^{2}}

\frac{n ^{4}}{5 n ^{- 2}}

What is (-(3x^4)/(2y^5))^{-3} ?
The solution to (-(3x^4)/(2y^5))^{-3} is -(8y^{15})/(27x^{12)}