What are the solutions to the equation x^2-x-1=-6x-1 ?

The solutions to the equation x^2-x-1=-6x-1 are x=0,x=-5

Find the zeros of x^2-x-1=-6x-1

The zeros of x^2-x-1=-6x-1 are x=0,x=-5

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x^{2} - x - 1 = - 6 x - 1

x = 0, x = - 5

Solution steps

x^{2} - x - 1 = - 6 x - 1

Move

1

to the left side

x^{2} - x = - 6 x

Move

6 x

to the left side

x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5}{2 \cdot 1}

x = \frac{- 5 + 5}{2 \cdot 1} : 0

x = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 0, x = - 5

(\frac{3 x ^{5} y ^{4}}{x ^{0} y ^{- 3}})^{2}

(2 - x)^{2} \leq 3

x^{2} + 12 x = 28

7 h^{4} - 7 p^{4}

What are the solutions to the equation x^2-x-1=-6x-1 ?
The solutions to the equation x^2-x-1=-6x-1 are x=0,x=-5
Find the zeros of x^2-x-1=-6x-1
The zeros of x^2-x-1=-6x-1 are x=0,x=-5