What is 2-5x^2+3x>= 0 ?

The solution to 2-5x^2+3x>= 0 is -2/5 <= x<= 1

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2-5x^2+3x>= 0

2 - 5 x^{2} + 3 x \geq 0

- \frac{2}{5} \leq x \leq 1

Interval Notation

[- \frac{2}{5}, 1]

Decimal Notation

- 0.4 \leq x \leq 1

Solution steps

2 - 5 x^{2} + 3 x \geq 0

Factor

2 - 5 x^{2} + 3 x : - (5 x + 2) (x - 1)

- (5 x + 2) (x - 1) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (5 x + 2) (x - 1)) (- 1) \leq 0 \cdot (- 1)

Simplify

(5 x + 2) (x - 1) \leq 0

Identify the intervals

- \frac{2}{5} \leq x \leq 1

- 16 \cdot - 81

5 b + 11 = 56 - 4 b

9 c + 12 = 27 - 3 c

(2 x - 1) - 4 (5 x - 2) \leq 9 - (6 x - 3)

t^{2} + 12 t + 36