What are the solutions to the equation p^2-2p-3=0 ?

The solutions to the equation p^2-2p-3=0 are p=3,p=-1

Find the zeros of p^2-2p-3=0

The zeros of p^2-2p-3=0 are p=3,p=-1

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p^{2} - 2 p - 3 = 0

p = 3, p = - 1

Solution steps

p^{2} - 2 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

p_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, p_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

p = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

p = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

p = 3, p = - 1

10 \leq r

\frac{1}{4} (4 y - 8) = 2 y - 9

(x + 1)^{2} + (- 2 x + 8)^{2} = 40

625 m^{5} - 256 m n^{4}

2 4^{2} + 7^{2} = c^{2}

What are the solutions to the equation p^2-2p-3=0 ?
The solutions to the equation p^2-2p-3=0 are p=3,p=-1
Find the zeros of p^2-2p-3=0
The zeros of p^2-2p-3=0 are p=3,p=-1