What is (x-7)/(2x+9)>= 1 ?

The solution to (x-7)/(2x+9)>= 1 is -16<= x<-9/2

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(x-7)/(2x+9)>= 1

\frac{x - 7}{2 x + 9} \geq 1

- 16 \leq x < - \frac{9}{2}

Interval Notation

[- 16, - \frac{9}{2})

Decimal Notation

- 16 \leq x < - 4.5

Solution steps

\frac{x - 7}{2 x + 9} \geq 1

Rewrite in standard form

\frac{- x - 16}{2 x + 9} \geq 0

Identify the intervals

- 16 \leq x < - \frac{9}{2}

x^{2} - 8 x + 64 = 0

(\frac{1}{36})^{x + 8} \leq 21 6^{x - 3}

\frac{8}{3} - 4

36 - 8

\frac{- 45 156}{9 3}