What are the solutions to the equation -3x^2+4x-7=0 ?

The solutions to the equation -3x^2+4x-7=0 are x= 2/3-i(sqrt(17))/3 ,x= 2/3+i(sqrt(17))/3

Find the zeros of -3x^2+4x-7=0

The zeros of -3x^2+4x-7=0 are x= 2/3-i(sqrt(17))/3 ,x= 2/3+i(sqrt(17))/3

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- 3 x^{2} + 4 x - 7 = 0

x = \frac{2}{3} - i \frac{17}{3}, x = \frac{2}{3} + i \frac{17}{3}

Solution steps

- 3 x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 3 ) ( - 7 )}{2 ( - 3 )}

Simplify

4^{2} - 4 (- 3) (- 7) : 217 i

x_{1, 2} = \frac{- 4 \pm 2 17 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 17 i}{2 ( - 3 )}, x_{2} = \frac{- 4 - 2 17 i}{2 ( - 3 )}

x = \frac{- 4 + 2 17 i}{2 ( - 3 )} : \frac{2}{3} - i \frac{17}{3}

x = \frac{- 4 - 2 17 i}{2 ( - 3 )} : \frac{2}{3} + i \frac{17}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} - i \frac{17}{3}, x = \frac{2}{3} + i \frac{17}{3}

x + 2 < - 1 or x + 3 \geq 2

x y^{2} - x^{3} y^{5}

(a^{- 5} b^{8} c^{- 12}) (a^{7} b^{- 3} c^{7})

2 x - 1 \leq 3

510 \cdot \frac{π}{180}

What are the solutions to the equation -3x^2+4x-7=0 ?
The solutions to the equation -3x^2+4x-7=0 are x= 2/3-i(sqrt(17))/3 ,x= 2/3+i(sqrt(17))/3
Find the zeros of -3x^2+4x-7=0
The zeros of -3x^2+4x-7=0 are x= 2/3-i(sqrt(17))/3 ,x= 2/3+i(sqrt(17))/3