What are the solutions to the equation 4y^2-1=0 ?

The solutions to the equation 4y^2-1=0 are y= 1/2 ,y=-1/2

Find the zeros of 4y^2-1=0

The zeros of 4y^2-1=0 are y= 1/2 ,y=-1/2

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4 y^{2} - 1 = 0

y = \frac{1}{2}, y = - \frac{1}{2}

Decimal Notation

y = 0.5, y = - 0.5

Solution steps

4 y^{2} - 1 = 0

Move

1

to the right side

4 y^{2} = 1

Divide both sides by

4

y^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{1}{4}, y = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

\frac{11 !}{8 !}

- 3 x + 8 \geq 14

x^{2} + x - 72 \leq 0

3 x^{2} + 14 x + 8 = 0

49 a^{2} + 14 a + 1

What are the solutions to the equation 4y^2-1=0 ?
The solutions to the equation 4y^2-1=0 are y= 1/2 ,y=-1/2
Find the zeros of 4y^2-1=0
The zeros of 4y^2-1=0 are y= 1/2 ,y=-1/2