What are the solutions to the equation (2x+7)^2=25 ?

The solutions to the equation (2x+7)^2=25 are x=-1,x=-6

Find the zeros of (2x+7)^2=25

The zeros of (2x+7)^2=25 are x=-1,x=-6

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(2 x + 7)^{2} = 25

x = - 1, x = - 6

Solution steps

(2 x + 7)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 7 = 25 : x = - 1

Solve

2 x + 7 = - 25 : x = - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

∣ x + 6 ∣ = ∣ 2 x + 2 ∣

4 - \frac{1}{2} w - \frac{1}{3} = \frac{1}{2}

\frac{n ^{\frac{3}{5}}}{n ^{- \frac{3}{4}}}

w^{2} - 5 w + 6 = 0

16 x^{2} y - 4 x y

What are the solutions to the equation (2x+7)^2=25 ?
The solutions to the equation (2x+7)^2=25 are x=-1,x=-6
Find the zeros of (2x+7)^2=25
The zeros of (2x+7)^2=25 are x=-1,x=-6