What are the solutions to the equation w^2-5w+6=0 ?

The solutions to the equation w^2-5w+6=0 are w=3,w=2

Find the zeros of w^2-5w+6=0

The zeros of w^2-5w+6=0 are w=3,w=2

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w^{2} - 5 w + 6 = 0

w = 3, w = 2

Solution steps

w^{2} - 5 w + 6 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

w_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, w_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

w = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

w = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

w = 3, w = 2

16 x^{2} y - 4 x y

4 ∣ x - 5 ∣ = 12

6 x^{2} + 6 x - 72 = 0

- 2 - (- 8)

3 r^{2} + r + 9 = 2

What are the solutions to the equation w^2-5w+6=0 ?
The solutions to the equation w^2-5w+6=0 are w=3,w=2
Find the zeros of w^2-5w+6=0
The zeros of w^2-5w+6=0 are w=3,w=2