What are the solutions to the equation 3r^2+r+9=2 ?

The solutions to the equation 3r^2+r+9=2 are r=-1/6+i(sqrt(83))/6 ,r=-1/6-i(sqrt(83))/6

Find the zeros of 3r^2+r+9=2

The zeros of 3r^2+r+9=2 are r=-1/6+i(sqrt(83))/6 ,r=-1/6-i(sqrt(83))/6

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3 r^{2} + r + 9 = 2

r = - \frac{1}{6} + i \frac{83}{6}, r = - \frac{1}{6} - i \frac{83}{6}

Solution steps

3 r^{2} + r + 9 = 2

Move

2

to the left side

3 r^{2} + r + 7 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

1^{2} - 4 \cdot 3 \cdot 7 : 83 i

r_{1, 2} = \frac{- 1 \pm 83 i}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- 1 + 83 i}{2 \cdot 3}, r_{2} = \frac{- 1 - 83 i}{2 \cdot 3}

r = \frac{- 1 + 83 i}{2 \cdot 3} : - \frac{1}{6} + i \frac{83}{6}

r = \frac{- 1 - 83 i}{2 \cdot 3} : - \frac{1}{6} - i \frac{83}{6}

The solutions to the quadratic equation are:

r = - \frac{1}{6} + i \frac{83}{6}, r = - \frac{1}{6} - i \frac{83}{6}

5 x^{2} + 10 x^{4}

5 z^{2} = 17 z - 14

\frac{( - 2 + 4 i )}{2 i}

- x + 5 < x + 3 \leq 2 x + 2

8 (m - 5) + 3 = 27

What are the solutions to the equation 3r^2+r+9=2 ?
The solutions to the equation 3r^2+r+9=2 are r=-1/6+i(sqrt(83))/6 ,r=-1/6-i(sqrt(83))/6
Find the zeros of 3r^2+r+9=2
The zeros of 3r^2+r+9=2 are r=-1/6+i(sqrt(83))/6 ,r=-1/6-i(sqrt(83))/6