What are the solutions to the equation 5x^2-18x+13=0 ?

The solutions to the equation 5x^2-18x+13=0 are x= 13/5 ,x=1

Find the zeros of 5x^2-18x+13=0

The zeros of 5x^2-18x+13=0 are x= 13/5 ,x=1

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5 x^{2} - 18 x + 13 = 0

x = \frac{13}{5}, x = 1

Decimal Notation

x = 2.6, x = 1

Solution steps

5 x^{2} - 18 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 5 \cdot 13}{2 \cdot 5}

(- 18)^{2} - 4 \cdot 5 \cdot 13 = 8

x_{1, 2} = \frac{- ( - 18 ) \pm 8}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 8}{2 \cdot 5}, x_{2} = \frac{- ( - 18 ) - 8}{2 \cdot 5}

x = \frac{- ( - 18 ) + 8}{2 \cdot 5} : \frac{13}{5}

x = \frac{- ( - 18 ) - 8}{2 \cdot 5} : 1

The solutions to the quadratic equation are:

x = \frac{13}{5}, x = 1

\frac{4 ( x + 1 )}{5} = 2 x - 4

(5 + x) \cdot (100 - 10 x) \geq 500

121 x^{2} + 638 x - 32648

\frac{y}{3} + 1 = 5

4 x (x^{3} - 6) - 7 (x^{3} - 6)

What are the solutions to the equation 5x^2-18x+13=0 ?
The solutions to the equation 5x^2-18x+13=0 are x= 13/5 ,x=1
Find the zeros of 5x^2-18x+13=0
The zeros of 5x^2-18x+13=0 are x= 13/5 ,x=1