What are the solutions to the equation (5x-2)^2=27 ?

The solutions to the equation (5x-2)^2=27 are x=(3sqrt(3)+2)/5 ,x=(-3sqrt(3)+2)/5

Find the zeros of (5x-2)^2=27

The zeros of (5x-2)^2=27 are x=(3sqrt(3)+2)/5 ,x=(-3sqrt(3)+2)/5

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(5 x - 2)^{2} = 27

x = \frac{3 3 + 2}{5}, x = \frac{- 3 3 + 2}{5}

Decimal Notation

x = 1.43923 \dots, x = - 0.63923 \dots

Solution steps

(5 x - 2)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 2 = 27 : x = \frac{3 3 + 2}{5}

Solve

5 x - 2 = - 27 : x = \frac{- 3 3 + 2}{5}

The solutions to the quadratic equation are:

x = \frac{3 3 + 2}{5}, x = \frac{- 3 3 + 2}{5}

x^{2} + 10 x + 3 = 0

2 x = 128

- \frac{w}{4} = 20

8 < 2 x < x + 8

8 x^{2} - 2 x - 3 = 0

What are the solutions to the equation (5x-2)^2=27 ?
The solutions to the equation (5x-2)^2=27 are x=(3sqrt(3)+2)/5 ,x=(-3sqrt(3)+2)/5
Find the zeros of (5x-2)^2=27
The zeros of (5x-2)^2=27 are x=(3sqrt(3)+2)/5 ,x=(-3sqrt(3)+2)/5