What are the solutions to the equation 9x^2-3x-6=0 ?

The solutions to the equation 9x^2-3x-6=0 are x=1,x=-2/3

Find the zeros of 9x^2-3x-6=0

The zeros of 9x^2-3x-6=0 are x=1,x=-2/3

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9 x^{2} - 3 x - 6 = 0

x = 1, x = - \frac{2}{3}

Decimal Notation

x = 1, x = - 0.66666 \dots

Solution steps

9 x^{2} - 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 6 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 6) = 15

x_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 9}

x = \frac{- ( - 3 ) + 15}{2 \cdot 9} : 1

x = \frac{- ( - 3 ) - 15}{2 \cdot 9} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{2}{3}

3 - (8 x - 5) + (6 - 7 x) + 3 = 7 x - (5 x + 9 - 3)

16 x^{2} - 48 x + 36

\frac{8}{9} - \frac{1}{6}

4 x^{2} - 7 x = 0

ab - 3 b + b^{2} - 3 a

What are the solutions to the equation 9x^2-3x-6=0 ?
The solutions to the equation 9x^2-3x-6=0 are x=1,x=-2/3
Find the zeros of 9x^2-3x-6=0
The zeros of 9x^2-3x-6=0 are x=1,x=-2/3