What are the solutions to the equation 0=4x-2x^2 ?

The solutions to the equation 0=4x-2x^2 are x=0,x=2

Find the zeros of 0=4x-2x^2

The zeros of 0=4x-2x^2 are x=0,x=2

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0 = 4 x - 2 x^{2}

x = 0, x = 2

Solution steps

0 = 4 x - 2 x^{2}

Switch sides

4 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 2 )}, x_{2} = \frac{- 4 - 4}{2 ( - 2 )}

x = \frac{- 4 + 4}{2 ( - 2 )} : 0

x = \frac{- 4 - 4}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

9 x + 27 = - 72

12 = x^{2} - 4 x

(x - 4)^{2}

2 x^{2} - 12 x - 6 = 0

\frac{1}{81} p - 16 p^{5}

What are the solutions to the equation 0=4x-2x^2 ?
The solutions to the equation 0=4x-2x^2 are x=0,x=2
Find the zeros of 0=4x-2x^2
The zeros of 0=4x-2x^2 are x=0,x=2