What are the solutions to the equation -9x^2+3x+469=439 ?

The solutions to the equation -9x^2+3x+469=439 are x=-5/3 ,x=2

Find the zeros of -9x^2+3x+469=439

The zeros of -9x^2+3x+469=439 are x=-5/3 ,x=2

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- 9 x^{2} + 3 x + 469 = 439

x = - \frac{5}{3}, x = 2

Decimal Notation

x = - 1.66666 \dots, x = 2

Solution steps

- 9 x^{2} + 3 x + 469 = 439

Move

439

to the left side

- 9 x^{2} + 3 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 9 ) \cdot 30}{2 ( - 9 )}

3^{2} - 4 (- 9) \cdot 30 = 33

x_{1, 2} = \frac{- 3 \pm 33}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 3 + 33}{2 ( - 9 )}, x_{2} = \frac{- 3 - 33}{2 ( - 9 )}

x = \frac{- 3 + 33}{2 ( - 9 )} : - \frac{5}{3}

x = \frac{- 3 - 33}{2 ( - 9 )} : 2

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = 2

3 (x + 2) (x - 2) = 0

4 (x - 1) + 4 x - 1 = 19

21000 + \frac{2}{7} + \frac{8}{21}

e^{- 4}

(5^{4})^{3}

What are the solutions to the equation -9x^2+3x+469=439 ?
The solutions to the equation -9x^2+3x+469=439 are x=-5/3 ,x=2
Find the zeros of -9x^2+3x+469=439
The zeros of -9x^2+3x+469=439 are x=-5/3 ,x=2