What are the solutions to the equation 3(x+2)(x-2)=0 ?

The solutions to the equation 3(x+2)(x-2)=0 are x=-2,x=2

Find the zeros of 3(x+2)(x-2)=0

The zeros of 3(x+2)(x-2)=0 are x=-2,x=2

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3 (x + 2) (x - 2) = 0

x = - 2, x = 2

Solution steps

3 (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - 2, x = 2

4 (x - 1) + 4 x - 1 = 19

21000 + \frac{2}{7} + \frac{8}{21}

e^{- 4}

(5^{4})^{3}

4 x^{2} + 23 x + 15 = 0

What are the solutions to the equation 3(x+2)(x-2)=0 ?
The solutions to the equation 3(x+2)(x-2)=0 are x=-2,x=2
Find the zeros of 3(x+2)(x-2)=0
The zeros of 3(x+2)(x-2)=0 are x=-2,x=2