What are the solutions to the equation 3x^2+13x+10=0 ?

The solutions to the equation 3x^2+13x+10=0 are x=-1,x=-10/3

Find the zeros of 3x^2+13x+10=0

The zeros of 3x^2+13x+10=0 are x=-1,x=-10/3

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3 x^{2} + 13 x + 10 = 0

x = - 1, x = - \frac{10}{3}

Decimal Notation

x = - 1, x = - 3.33333 \dots

Solution steps

3 x^{2} + 13 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 \cdot 10 = 7

x_{1, 2} = \frac{- 13 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 13 + 7}{2 \cdot 3}, x_{2} = \frac{- 13 - 7}{2 \cdot 3}

x = \frac{- 13 + 7}{2 \cdot 3} : - 1

x = \frac{- 13 - 7}{2 \cdot 3} : - \frac{10}{3}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{10}{3}

1 x + 5 \geq - 16

(x^{8} y^{4})^{\frac{1}{10}} + 3 (x^{\frac{1}{5}} y^{\frac{1}{10}})^{4}

96 x^{2} + 12 = 0

10 - 2 (2 x - 4) = (3 x + 4) 2

0. 6^{3}

What are the solutions to the equation 3x^2+13x+10=0 ?
The solutions to the equation 3x^2+13x+10=0 are x=-1,x=-10/3
Find the zeros of 3x^2+13x+10=0
The zeros of 3x^2+13x+10=0 are x=-1,x=-10/3