What are the solutions to the equation 2a^2+8a=-12 ?

The solutions to the equation 2a^2+8a=-12 are a=-2+sqrt(2)i,a=-2-sqrt(2)i

Find the zeros of 2a^2+8a=-12

The zeros of 2a^2+8a=-12 are a=-2+sqrt(2)i,a=-2-sqrt(2)i

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2 a^{2} + 8 a = - 12

a = - 2 + 2 i, a = - 2 - 2 i

Solution steps

2 a^{2} + 8 a = - 12

Move

12

to the left side

2 a^{2} + 8 a + 12 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

Simplify

8^{2} - 4 \cdot 2 \cdot 12 : 42 i

a_{1, 2} = \frac{- 8 \pm 4 2 i}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 8 + 4 2 i}{2 \cdot 2}, a_{2} = \frac{- 8 - 4 2 i}{2 \cdot 2}

a = \frac{- 8 + 4 2 i}{2 \cdot 2} : - 2 + 2 i

a = \frac{- 8 - 4 2 i}{2 \cdot 2} : - 2 - 2 i

The solutions to the quadratic equation are:

a = - 2 + 2 i, a = - 2 - 2 i

- 3 ∣ x ∣ = 0

8 x + 9 - 12 x = 4 x - 13 - 5 x

4 x^{2} - 2 x = 23

- x^{2} + 10 x - 24 = 0

- 12 + 5 (7 p + 3) - 28 p < 3 p - 17

What are the solutions to the equation 2a^2+8a=-12 ?
The solutions to the equation 2a^2+8a=-12 are a=-2+sqrt(2)i,a=-2-sqrt(2)i
Find the zeros of 2a^2+8a=-12
The zeros of 2a^2+8a=-12 are a=-2+sqrt(2)i,a=-2-sqrt(2)i