What is (2x+1)/(3x-1)>(2x+5)/(3x+2) ?

The solution to (2x+1)/(3x-1)>(2x+5)/(3x+2) is x<-2/3 \lor 1/3 <x< 7/6

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(2x+1)/(3x-1)>(2x+5)/(3x+2)

\frac{2 x + 1}{3 x - 1} > \frac{2 x + 5}{3 x + 2}

x < - \frac{2}{3} or \frac{1}{3} < x < \frac{7}{6}

Interval Notation

(- \infty, - \frac{2}{3}) \cup (\frac{1}{3}, \frac{7}{6})

Decimal Notation

x < - 0.66666 \dots or 0.33333 \dots < x < 1.16666 \dots

Solution steps

\frac{2 x + 1}{3 x - 1} > \frac{2 x + 5}{3 x + 2}

Rewrite in standard form

\frac{- 6 x + 7}{( 3 x - 1 ) ( 3 x + 2 )} > 0

Identify the intervals

x < - \frac{2}{3} or \frac{1}{3} < x < \frac{7}{6}

\frac{π}{2} \cdot 2 π

\frac{e ^{6 i} - e ^{- 6 i}}{2 i}

- 2 (u + 2) + 7 = 3 (u + 6)

9 x^{2} - 7 x = 4

3^{5} \cdot 5^{3}

What is (2x+1)/(3x-1)>(2x+5)/(3x+2) ?
The solution to (2x+1)/(3x-1)>(2x+5)/(3x+2) is x<-2/3 \lor 1/3 <x< 7/6