What are the solutions to the equation (x-3)^2=-4 ?

The solutions to the equation (x-3)^2=-4 are x=2i+3,x=-2i+3

Find the zeros of (x-3)^2=-4

The zeros of (x-3)^2=-4 are x=2i+3,x=-2i+3

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(x - 3)^{2} = - 4

x = 2 i + 3, x = - 2 i + 3

Solution steps

(x - 3)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 4 : x = 2 i + 3

Solve

x - 3 = - - 4 : x = - 2 i + 3

The solutions to the quadratic equation are:

x = 2 i + 3, x = - 2 i + 3

1 x^{2} + 5 x + 6 = 0

63 x^{12} - 35 x^{6}

3 x - 1 = 20

\frac{x ^{- 4}}{x ^{- 9}}

X + 3 (X + 8) = 7 (X + 4)

What are the solutions to the equation (x-3)^2=-4 ?
The solutions to the equation (x-3)^2=-4 are x=2i+3,x=-2i+3
Find the zeros of (x-3)^2=-4
The zeros of (x-3)^2=-4 are x=2i+3,x=-2i+3