What are the solutions to the equation -2x^2-41x-106=-13x ?

The solutions to the equation -2x^2-41x-106=-13x are x=-7-2i,x=-7+2i

Find the zeros of -2x^2-41x-106=-13x

The zeros of -2x^2-41x-106=-13x are x=-7-2i,x=-7+2i

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- 2 x^{2} - 41 x - 106 = - 13 x

x = - 7 - 2 i, x = - 7 + 2 i

Solution steps

- 2 x^{2} - 41 x - 106 = - 13 x

Move

13 x

to the left side

- 2 x^{2} - 28 x - 106 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 ( - 2 ) ( - 106 )}{2 ( - 2 )}

Simplify

(- 28)^{2} - 4 (- 2) (- 106) : 8 i

x_{1, 2} = \frac{- ( - 28 ) \pm 8 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 8 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 28 ) - 8 i}{2 ( - 2 )}

x = \frac{- ( - 28 ) + 8 i}{2 ( - 2 )} : - 7 - 2 i

x = \frac{- ( - 28 ) - 8 i}{2 ( - 2 )} : - 7 + 2 i

The solutions to the quadratic equation are:

x = - 7 - 2 i, x = - 7 + 2 i

x^{2} - 12 x + 24 = 0

- 6 < x < 5

∣ - 4 ∣

x^{3} + 2 x^{2} - 16 x - 32

7 x + 39 \geq 53 and 16 x + 15 > 31

What are the solutions to the equation -2x^2-41x-106=-13x ?
The solutions to the equation -2x^2-41x-106=-13x are x=-7-2i,x=-7+2i
Find the zeros of -2x^2-41x-106=-13x
The zeros of -2x^2-41x-106=-13x are x=-7-2i,x=-7+2i