What are the solutions to the equation -15x^2+28x-5=0 ?

The solutions to the equation -15x^2+28x-5=0 are x= 1/5 ,x= 5/3

Find the zeros of -15x^2+28x-5=0

The zeros of -15x^2+28x-5=0 are x= 1/5 ,x= 5/3

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- 15 x^{2} + 28 x - 5 = 0

x = \frac{1}{5}, x = \frac{5}{3}

Decimal Notation

x = 0.2, x = 1.66666 \dots

Solution steps

- 15 x^{2} + 28 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 ( - 15 ) ( - 5 )}{2 ( - 15 )}

2 8^{2} - 4 (- 15) (- 5) = 22

x_{1, 2} = \frac{- 28 \pm 22}{2 ( - 15 )}

Separate the solutions

x_{1} = \frac{- 28 + 22}{2 ( - 15 )}, x_{2} = \frac{- 28 - 22}{2 ( - 15 )}

x = \frac{- 28 + 22}{2 ( - 15 )} : \frac{1}{5}

x = \frac{- 28 - 22}{2 ( - 15 )} : \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = \frac{5}{3}

16 x^{2} - 40 x + 25

222

\frac{- 3 ( x + 3 )}{2} \leq 6

y^{2} + 8 y + 12

49 - 64 x^{2}

What are the solutions to the equation -15x^2+28x-5=0 ?
The solutions to the equation -15x^2+28x-5=0 are x= 1/5 ,x= 5/3
Find the zeros of -15x^2+28x-5=0
The zeros of -15x^2+28x-5=0 are x= 1/5 ,x= 5/3